Answer: a) AB = ![\left[\begin{array}{ccc}-14&26\\-11&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14%2626%5C%5C-11%2622%5Cend%7Barray%7D%5Cright%5D)
; b) ![\left[\begin{array}{ccc}5&-5\\13&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C13%269%5Cend%7Barray%7D%5Cright%5D)
; c) No, they are different; d) No, they are never the same;
Step-by-step explanation:
a) A = ![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
, B = ![\left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C-3%267%5Cend%7Barray%7D%5Cright%5D)
. This multiplication is possible, because matrix A has 2 columns and matrix B has 2 rows. When those value are equal, the multiplication is possible.
AB = . =
b) BA = . =
c) As, we can see, parts a and b are differents.
d) With matrices, multiplication is not commutative, which means AB≠BA
Answer:
AB = 5 units
BC = 5
units
AC = 
or about 6.4 units
Step-by-step explanation:
distance formula: square root of the sum of the difference of the y-values and the difference of the x-values
ex, dAB = √(4-0)² + (3-0)²
= √16 + 9
= √25
= 5
