1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brilliant_brown [7]
3 years ago
14

How to calculate this question?

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

if you use perimeter area you can get answer

You might be interested in
Suppose that 80 percent of all statisticians are shy, whereas only 15 percent of all economists are shy. Suppose also that 90 pe
Anna71 [15]

Answer:

37.21% probability that the person is a statistician.

Step-by-step explanation:

We have these following probabilities:

An 80% probability that a statistican is shy.

A 15% probability that an economist is shy.

At the gathering, a 90% probability that a person is an economist.

At the gathering, a 10% probability that a person is a statistican.

If you meet a shy person at random at the gathering. What is the probability that the person is a statistician?

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the person is a statistican, given that he is shy?

P(B) is the probability of the person being a statistican. So P(B) = 0.1.

P(A/B) is the probability of a statistican being shy, so P(A/B) = 0.8.

P(A) is the probability of a person being a shy. This is 15% of 90%(economists) and 80% of 10%(statisticans). So

P(A) = 0.15*0.9 + 0.8*0.1 = 0.215

Finally

P = \frac{P(B).P(A/B)}{P(A)}

P = \frac{0.1*0.8}{0.215} = 0.3721

37.21% probability that the person is a statistician.

3 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST ​
kobusy [5.1K]

Answer:

If using one pound of pumpkin the baker needs to use 4 pounds of flour mixture

Step-by-step explanation:

step 1: I am going to convert the measurements

into decimals

8/5=1.6

2/5=.4

step 2: I will use cross multiplication to find out how much pumpkin for one pound of flour

1.6=.4

 1=?

1*.4=.4/1.6=.25

step 3:  I will convert .25 into a fraction

.25=1/4

for every 1/4 pound pumpkin, I will use 1 pound of flour

which is why

If using one pound of pumpkin the baker needs to use 4 pounds of flour mixture

6 0
2 years ago
Can someone help me with this question
Dmitriy789 [7]

Answer:

The horizontal shift is to the left by 2 units and the vertical shift is down 3 units for this function.

I hope I was able to help!

Step-by-step explanation:

7 0
2 years ago
Use the graph below to choose the correct statements. Select all that apply
kati45 [8]
Is there any duplicate in x-value wrt y-value if you apply the vertical line test?
 <span />
3 0
3 years ago
Expand and simplify: (x-5)(x+5)
stealth61 [152]
X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)





5 0
3 years ago
Read 2 more answers
Other questions:
  • If (x,y) is a solution to the system of equations shown below, what is the product of the y-coordinates of the solutions? x^2+4y
    12·1 answer
  • 2. What is the value of x in this diagram?
    13·1 answer
  • What percent of 80 is 200?
    7·2 answers
  • Hadley's softball team has a phone tree in case a game is canceled.
    10·1 answer
  • Identify the x-intercept of the linear equation 3x+y-9=0
    5·1 answer
  • Question 3 (1 point)
    12·2 answers
  • In which quadrant does angle theta lie if csc theta &lt;0 and cot theta&lt;0?
    10·1 answer
  • 14 4/9+ 25 1/6+ 7 11/18=
    9·2 answers
  • Need help on this is mathhhhhhhhhhhhhhhhhhhhhhhhh
    10·1 answer
  • 50 points please help<br><br> please explain your answer please ( such as formula n such )
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!