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butalik [34]
3 years ago
14

Help em with this plss

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

Answer:

the first one

Step-by-step explanation:

\frac{4}{5} + \frac{1}{2} = \frac{13}{10} = 1\frac{3}{10}

jeka943 years ago
4 0

Answer:

1 3/10

Step-by-step explanation:

4/5 + 1/2

Get a common denominator of 10

4/5 * 2/2+ 1/2 * 5/5

8/10 + 5/10

13/10

Rewriting

10/10 + 3/10

1 3/10

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
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Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

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Answer:

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