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2 years ago

Write a subtraction expression with a positive and negative integer whose difference is negative. Then find the difference

Mathematics

1 answer:

horrorfan [7]2 years ago

5 0

Answer:

-20-15=-35

Step-by-step explanation:

I think this answers your question, sorry if I'm wrong!

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Which is the value of this expression when a=5 and k=-2

Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

$(\frac{3^2a^{-2}}{3a^{-1}})^k$

The value of a =5 and k = -2

Putting the values and solving

$=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}$

Option C is correct.

3 0

3 years ago

HURRY BRAINLIEST AND 40 POINTS!!!

olganol [36]

ANSWER:
Instead of greater than, the inequity symbol should be greater than or or equal to.

Step-by-step explanation:
We know the variable x represents the number of students. We also know there are 5 chaperones attending; this makes x+5 , by 2.50
It costs $2.50 per person; this means we multiply the number of people, x+5, by 2.50:

2.50(x+5)

The class has $90 to spend; this means they can spend up to and including $90. This gives us
90>2.50(x+5)
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3 0

3 years ago

Read 2 more answers

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago

What is the average of 63 and 148

fgiga [73]

The average is 105.5. To find the average, you have to add up all numbers, 63+148=211. Now you have to divide by how many numbers there are, 211÷2=105.5

8 0

3 years ago

I need some help on this one

Gennadij [26K]

Answer:

3°

Step-by-step explanation:

5 0

2 years ago