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Marrrta [24]
3 years ago
14

Kim's class voted on a location for a field trip. 3/4 of the class voted for the museum. 1/8 of the class voted for the zoo. The

rest of the class voted for the nature park. What fraction of the class voted for the nature park?
Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

1/8

Step-by-step explanation:

3/4 is the same as 6/8. 6/8 plus 1/8 is 7/8. 8/8 minus 7/8 is 1/8.

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(WILL MARK AS BRAINLEIST)
Bogdan [553]

Answer:

Step-by-step explanation:

20%

8 0
3 years ago
Read 2 more answers
How to substitute x=-2 and x=5 into 2x^2+6-20=0 to check my work
Komok [63]
First answer (x=-2)
...
(2)[(-2)^2]+6-20
2(4)+6-20
8+6-20
14-20
<em>-6 (answer)
</em><em>
</em><em />Second answer (x=5)
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(2)[(-5)^2]+6-20
2(25)+6-20
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<em>36 (answer)
</em>Hope this helps!
4 0
3 years ago
Is (10,4),(-2,4),(-1,1),(5,6) a function?
lys-0071 [83]
No it is not a function.
7 0
1 year ago
Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.
pashok25 [27]

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* <em>Lets explain How to solve the problem</em>

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- <em>The length of QS is the sum of the lengths of QR and RS</em>

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- <em>To find the length of RS substitute the value of x in its expression</em>

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

8 0
3 years ago
Jessica and Riley are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping
bixtya [17]

Answer:

Cost of one roll of plain wrapping: \$5

Cost of one roll of holiday wrapping paper:  \$19

Step-by-step explanation:

Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.

Based on the information given, we can set up this system of equations:

\left \{ {{5p+13h=272} \atop {11p+16h=359}} \right.

In order to solve it, we can use the Substitution method. The steps are:

1. Solve for "p" from the first equation:

5p+13h=272\\\\5p=272-13h\\\\p=\frac{272-13h}{5}

2. Substitute the above into the second equation and solve for "h":

11(\frac{272-13h}{5})+16h=359\\\\598.4-28.6h+16h=359\\\\-12.6h=359-598.4\\\\h=\frac{-239.4}{-12.6}\\\\h=19

3. Substitute the value of "h" into p=\frac{272-13h}{5}:

p=\frac{272-13(19)}{5}\\\\p=5

7 0
3 years ago
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