if the apy of a savings account is 3.9% and if the principal in the savings account is $3,700 for an entire year what will be th
1 answer:
Answer:
The balance of the savings account after all the interest is paid for the year is $3,844.30
Step-by-step explanation:
In the question we have been given the Annual percentage yield as 3.9% , the principal as 3,700 and the time to be 1 year and asked to determine the accumulated amount in the savings account at the end of the year.
The accumulated amount can be determined using the compound interest formula;
Therefore, the balance of the savings account after all the interest is paid for the year is $3,844.30
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Answer:
Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078
Step-by-step explanation:
We are given the following in the question:
According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight.
Sample size, n = 1200
p = 7.8% = 0.078
We have to carry a hypothesis test whether national percentage is higher than 7.8% or not.
Thus, we can design the null and the alternate hypothesis
Thus, the correct answer is:
Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078
Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92
The 90th percentile score is nothing but the x value for which area below x is 90%.
To find 90th percentile we will find find z score such that probability below z is 0.9
P(Z <z) = 0.9
Using excel function to find z score corresponding to probability 0.9 is
z = NORM.S.INV(0.9) = 1.28
z =1.28
Now convert z score into x value using the formula
x = z *σ + μ
x = 1.28 * 92 + 1028
x = 1145.76
The 90th percentile score value is 1145.76
The probability that randomly selected score exceeds 1200 is
P(X > 1200)
Z score corresponding to x=1200 is
z =
z =
z = 1.8695 ~ 1.87
P(Z > 1.87 ) = 1 - P(Z < 1.87)
Using z-score table to find probability z < 1.87
P(Z < 1.87) = 0.9693
P(Z > 1.87) = 1 - 0.9693
P(Z > 1.87) = 0.0307
The probability that a randomly selected score exceeds 1200 is 0.0307