The answer in slope intercept form is y = 6x-11
If you want the answer in standard form, then it would be 6x-y =11
notes:
* Slope intercept form is y = mx+b
* Standard form is Ax+By = C
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Explanation:
The given slope is m = 6
The line goes through (x,y) = (3,7)
Plug those three values into the equation below. Isolate b
y = mx+b
7 = 6*3+b
7 = 18+b
7-18 = 18+b-18 ... subtract 18 from both sides
-11 = b
b = -11
So because m = 6 and b = -11, this means y = mx+b turns into y = 6x-11
The answer in slope intercept form is y = 6x-11
To convert to standard form Ax+By = C, we just have to get all the x and y terms together on the same side. I'm going to move the y term to the right side and move the 11 to the left side
y = 6x-11
y+11 = 6x-11+11
y+11 = 6x
y+11-y = 6x-y
11 = 6x-y
6x-y = 11
The answer in standard form is
6x-y = 11
which is a different way to write the same line
2ax-7a-2bx+7b
1.)multiply the twos together.
4ax-7a-2bx+7b
2.) subtract 4a from 7a
-3ax-2bx+7b
3)Combine like terms
6ax^2+7b
Answer:
0.002 is the kiloliter and if you multiply you get 0.005
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
We are given the following information:
We treat adult who prefer one child to be a boy as a success.
P(prefer one child to be a boy) = 40% = 0.4
Then the number of adults follows a binomial distribution, where
![P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%5Cbinom%7Bn%7D%7Bx%7D.p%5Ex.%281-p%29%5E%7Bn-x%7D)
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 15 and x = 8
We have to evaluate:
![P(x \geq 8)\\= P(x = 8) + P(x = 9)+...+ P(x = 14) + P(x =15)\\\\= \binom{15}{8}(0.4)^{8}(1-0.4)^{7} +\binom{15}{9}(0.4)^{9}(1-0.4)^{6}+...\\\\...+\binom{15}{14}(0.4)^{14}(1-0.4)^{1} +\binom{15}{8}(0.4)^{15}(1-0.4)^{0}\\\\= 0.2131](https://tex.z-dn.net/?f=P%28x%20%5Cgeq%208%29%5C%5C%3D%20P%28x%20%3D%208%29%20%2B%20P%28x%20%3D%209%29%2B...%2B%20P%28x%20%3D%2014%29%20%2B%20P%28x%20%3D15%29%5C%5C%5C%5C%3D%20%5Cbinom%7B15%7D%7B8%7D%280.4%29%5E%7B8%7D%281-0.4%29%5E%7B7%7D%20%2B%5Cbinom%7B15%7D%7B9%7D%280.4%29%5E%7B9%7D%281-0.4%29%5E%7B6%7D%2B...%5C%5C%5C%5C...%2B%5Cbinom%7B15%7D%7B14%7D%280.4%29%5E%7B14%7D%281-0.4%29%5E%7B1%7D%20%2B%5Cbinom%7B15%7D%7B8%7D%280.4%29%5E%7B15%7D%281-0.4%29%5E%7B0%7D%5C%5C%5C%5C%3D%200.2131)
Since the probability of 8 or more is 0.2131 is not very small, thus, it is not a rare event.
Thus, the given statement is false.