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LenKa [72]
3 years ago
11

Figure EFGH is a trapezoid. Trapezoid E F G H is shown. Sides E F and H G are parallel. Angle H is a right angle. Angle E is (9

x) degrees, angle F is (14 x) degrees, and angle G is (4 x) degrees. What is the measure of angle F

Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

The Answer is C

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at Alan's sports shop, GO FAST trainers cost £40.95 originally and there is a third off in the sale.  At  Irene's sport shop, GO
dem82 [27]
The trainers will be cheaper at Alan's sport shop.

prices ->
Alan's: 27.30
Irene's: 28.00

\frac{1}{3} of 40.95 can be calculated as follows ->

\frac{1}{3} = \frac{x}{40.95}
simplify to get that x = 27.30

30% of 40.00 can be calculated as follows ->

\frac{30}{100} = \frac{x}{40.00}
simplify to get that x = 28
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The amount y of your​ friend's allowance if the amount she receives is ​$10 more than the amount x you receive.
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X + $10 is the equation
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Kiran wrote the expression x-10 for this number puzzle: "Pick a number, add -2, and multiply by 5."
ioda

Answer:

If you pick the number 2, you will get (2) - 10 = 8

But the way he said it, it would be:  (2) - 2 * 5 = 0

The correct way would be to write the expression:  (x - 3) * 5

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If you get this you are a critical thinker.
Alchen [17]

Answer:

5

Step-by-step explanation:

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Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
2 years ago
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