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Lynna [10]
2 years ago
11

Find the difference: -4- (-3) =

Mathematics
2 answers:
GarryVolchara [31]2 years ago
7 0

Answer:

<h2>-1</h2>

Step-by-step explanation:

-4 - (-3)

= -4 + 3

= -1

<h3>#AyoBelajar</h3>
Sidana [21]2 years ago
4 0

Answer:

(-1)

Step-by-step explanation:

-4- (-3)

-4+3

(-1)

<em>Hope you got it </em>

<em>If you have any question just ask me</em>

<em>If you think this is the best answer please mark me as brainliest</em>

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Simplify the expression. 15+​(−4​)− 4/5j− 2/5j+6
Charra [1.4K]

Answer:

85j-6/5j

Step-by-step explanation:

4 0
3 years ago
What algebraic expression is used below. 5+3(2x-7)=5+6-21
Alla [95]

It appears like the 3 was distributed through the parenthesis

7 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
2 years ago
Approximate 218.16 to the nearest tens.
luda_lava [24]
218.16 to the nearest tenth would be 218
3 0
2 years ago
Explain the distance formula. Then use it to calculate the distance between A(1,1) and B (7,-7)
crimeas [40]

The distance formula is given by:

d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }

We are given two points A and B as

A(1,1) and

B(7,-7)

so we have ,

x1 = 1 , y1=1

x2= 7 and y2=-7

Plugging these in the formula we have:

d=\sqrt{(7-1)^{2}+(-7-1)^{2} }

d=√(36+64)

d=√100

d=10

Answer: The distance between A(1,1) and B(7,-7) is 10

4 0
3 years ago
Read 2 more answers
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