Question

Which equation can be used to represent six added to twice the sum of a numbee and four is equal to one half of the difference of three and the number

Answer 1

Answer:  $6 + 2 (x+4)$ =   $\frac{3}{2}$$(3-x)$

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

$6 + 2 (x+4)$

one half of the difference of three and the number means :

$\frac{3}{2}$$(3-x)$

combining the two , we have

$6 + 2 (x+4)$ = $\frac{3}{2}$$(3-x)$