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3 years ago

List all info given by the marks on the diagram.

Mathematics

1 answer:

Ne4ueva [31]2 years ago

5 0

Honestly I tried looking it up to get atleast something, but my best answer would have to be B.

Take this answer with a grain of salt, a lot of it

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13 points so please help meee with a and b!

yawa3891 [41]

Answer:

(a)

$24.10,

$18.20,

$15.25,

$9.35,

$0.50,

(b)

b=30-2.95g

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Complete the following statement.<br><br> 16 fl oz = pt

Elden [556K]

Answer:

Step-by-step explanation:

divide the volume value by 16

6 0

3 years ago

Ahmad and Ben have a total of 78 keychains.

Murljashka [212]

Sorry it was tru

2C=B

C-A=6 A=C-6

A+B+C=78

78=C-6+2C+C

5 0

2 years ago

Cassie has test grades of 62, 85 and 89 on the first three tests in herpre-algebra class. What are the possible scores she can m

Vsevolod [243]

Explanation:

The test grade for 1st three tests = 62, 85, 89

Let the fourth test score = x

The result we hoping to get is grade B.

Let's find the average of the four test score

$\text{Average = }\frac{Su\text{ m of all test score}}{nu\text{mber of test score}}$ $\begin{gathered} s\text{ um of test scores = 62 + 85 + 89 + x} \\ nu\text{mber of test score = 4} \\ \frac{\text{62 + 85 + 89 + x}}{4}=\text{ Average} \end{gathered}$ $\begin{gathered} A\text{ grade B represents atleast 80} \\ \text{Atleast represents }\ge \\ \frac{\text{62 + 85 + 89 + x}}{4}\text{ }\ge\text{ 80} \\ \frac{\text{236 + x}}{4}\text{ }\ge\text{ 80} \end{gathered}$ $\begin{gathered} \text{236 + x }\ge\text{ }80(4) \\ \text{236 + x }\ge\text{ }320 \\ \text{subtract }236\text{ from both sides:} \\ 236\text{ - 236 + x }\ge\text{ }320\text{ - 23}6 \\ x\text{ }\ge\text{ 84} \end{gathered}$

This means Cassie needs to score 84 or more to get a grade of B

In ineq

3 0

1 year ago

What are the real zeros of the function g(x)=x^3+2x^2-x-2

Gre4nikov [31]

$g(x)=x^3+2x^2-x-2\\\\\text{The zeros:}\\\\g(x)=0\to x^3+2x^2-x-2=0\\\\x^2(x+2)-1(x+2)=0\\\\(x+2)(x^2-1)=0\iff x+2=0\ \vee\ x^2-1=0\\\\x+2=0\ \ \ |-2\\x=-2\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt{1}\to x=-1\ \vee\ x=1\\\\\text{Answer:}\ x=-2\ or\ x=-1\ or\ x=1$

4 0

2 years ago