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2 years ago

Evaluate 48×15^2-5^2×2×24 by using factorisation and algebraic identities.

Mathematics

1 answer:

nikklg [1K]2 years ago

4 0

Step-by-step explanation:

$9600$

This is your answer

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If the circumference of a circle is 120 inches and M angle B equals 18° then what is the length of arc AC

Andru [333]

Answer:

For a circle of radius R, the circumference is:

C = 2*pi*R

where pi = 3.14

And if we have an arc defined by an angle θ, the length of the arc is:

A = (θ/360°)*2*pi*R

Here we can not see the image, then i assume that B is the angle that defines the arc AC.

Now we know that the circumference is 120 in, then:

2*pi*R = 120in

Then the length of the arc is:

A = (θ/360°)*120 in

Then if the angle is 18°, we have:

A = (18°/360)*120 in = 6in

6 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

MAVERICK [17]

The answer is 18.2% I believe.

3 0

3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

2 years ago

a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long

QveST [7]

Answer:

10.1 years.

Step-by-step explanation:

It is given that,

Principal = 9000

Rate of interest = 5%

No. of times interest compounded = 2 times in an year

Amount after certain time = 14800

The formula for amount:

$A=P(1+\frac{r}{n})^{nt}$

where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.

Substitute the given values in the above formula.

$14800=9000(1+\frac{0.05}{2})^{2t}$

$\frac{14800}{9000}=(1+0.025)^{2t}$

$1.644=(1.025)^{2t}$

Taking log both sides.

$\log(1.644)=\log(1.025)^{2t}$

$\log(1.644)=2t\log(1.025)$ $[\because \log a^b=b\log a]$

$\frac{\log(1.644)}{2\log(1.025)}=t$

$t=10.066$

$t=10.1$

Therefore, the required time is 10.1 years.

3 0

3 years ago

Find a real number between -3 and 5 a : -4 b : 1 c : -5 d : 6

Bumek [7]

The answer is 1.
Reasons : All the other answer choices are either below -3 or after 5.

8 0

2 years ago