Least common multiple 14,6
1 answer:
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Penjelasan langkah demi langkah:
1)
2) √32 +3√18-2√50
= √16*2 +3√9*2-2√25*2
= 4√2 + 3(3√2)-2(5√2)
= 4√2 + 9√2-10√2
= 13√2-10√2
= 3√2
3) 1000 ⅔×64⅙
4) 3/4+√2
5) 2√3×√18
= 2√3×√9*2
= 2√3×3√2
= (2*3)(√3*√2)
= 6√6
6) 12/3+√3
= 4+√3
7) √1000—2√40
= 10 -2 (√4*10)
= 10-2(2√10)
= 10 - 4√10
8) 2- ¹+3-¹
9)
Jika pernyataannya opsional, penyebutnya adalah 1
10) 2√3×√18
= 2√3×√9*2
= 2√3×3√2
= (2*3)(√3*√2)
= 6√6
The advance tickets were 35 in number and the same day ticket will be 30 in number.
<h3>What will be the number of tickets?</h3>To find out the number of the tickets sold we will give some notations so the notations are as follows:-
A= Cost of advance tickets=$30
S= cost of same-day ticket-=15
Number of the advance tickets
Number of same-day tickets.
The equations made by the given data will be:-
By solving the above equations:-
Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.
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