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2 years ago

4 1/5 ÷ 2/3 as a mixed number in simplest form

Mathematics

1 answer:

Lady_Fox [76]2 years ago

8 0

Answer:

Step-by-step explanation:

$4 \frac{1}{5} \div \frac{2}{3} = \frac{21}{5} \div \frac{2}{3} = \frac{21}{5} \times \frac{3}{2 } \\ \\ = \frac{63}{10} = 6 \frac{3}{10}$

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3 years ago

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Short Response<br> 6. Are the triangles at the right simílar? Explain.

Taya2010 [7]

Answer:

Yes they are similar because they are both right angles but the one on the right is bigger than the one on the left.

Step-by-step explanation:

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3 years ago

The top of two poles of height's 20m and 14m are connected by the wire

Hatshy [7]

Answer:

The correct option is;

10 m

Step-by-step explanation:

The parameters given are;

Height of the first pole = 20 m

Height of the second pole = 14 m

The angle the wire connected to their top makes with the horizontal = 30°

The vertical height subtended by the inclined wire, h = The difference in height between the two poles = 20 - 14 = 6 m.

Let the horizontal distance between the two poles = D

Therefore;

The horizontal length of the wire = D

From trigonometric ratios, we have;

$tan(30 ^{\circ}) = \dfrac{h}{D} = \dfrac{6}{D}$

Which gives;

$D = \dfrac{6}{tan(30 ^{\circ}) } = 10.39 \ m\approx 10 \ m$

The correct option is 10 m.

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3 years ago

What is question is asking

Pachacha [2.7K]

A) 72/910
b) 278/910
c) 57/910
d1) same as c) = 57/910
d2) 120/910
d3) 101/910
e) No, they DEPENDANT.
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3 years ago

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

3 years ago