How do you find the ratio of x and y coordinates

Mathematics

1 answer:

Firdavs [7]2 years ago

6 0

Answer:

(in step-by-step explanation)

Step-by-step explanation:

The ratio x:y is the same as the fraction x/y if that helps, so it is basically putting the coordinates into a fraction. Here is a video that might help also: https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-ratios-prop-topic/cc-6th-ratio-word-problems/v/ratios-on-coordinate-plane

Coordinate planes are a way of expressing data, so if it makes it easier, put the data into a ratio! Sorry, it is a bit difficult to explain such a broad question.

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What is the value of x? enter your answer in the box

antiseptic1488 [7]

Answer:

2(x+10) = 3x-30 (reason: vertical angles are congruent)

2x+20 = 3x-30

20 = 1x-30

1x = 20+30

1x = 50

x = 50

5 0

3 years ago

Read 2 more answers

5x^2-2x=2 help plsmmm

Yuki888 [10]

Answer:

Presumably you're solving for x here? Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

$5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\$

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

$25x^2 - 10x - 10 = 0\\$

Now we'll add 11 to both sides:

$25x^2 - 10x + 1 = 11\\$

Which makes the left side a perfect square:

$(5x - 1)^2 = 11$

And now we can solve for x:

$(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}$

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

$x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86$ $x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46$