Answer:
D. 0.925x + 0.88y = 0.91(x + y)
Step-by-step explanation:
The important point to remember is that the total mass of pure silver is the same on each side of the equation.
0.925x = mass of pure silver in first alloy
0.88 y = mass of pure silver in second alloy
The final alloy has a mass of (x + y) g and is 91 % pure silver, so
0.925x + 0.88y = 0.91(x + y)
Answer:
a) 1.8 × 10^-12 cm³ or 1.8 × 10^-12 cubic meters
b) 7.1 × 10^-6 mm² or 7.1 × 10^-6 square millimeters
Step-by-step explanation:
a) We are assuming that the shape of the bacteria is a sphere.
Hence, Volume of the Sphere(Bacteria) = 4/3 × π × r³
Diameter = 1.5 μm
Radius = Diameter/2 = 1.5μm/2
= 0.75μm
We are told that the volume should be in cubic centimeters
Converting 0.75μm to centimeters
1 μm = 1 × 10^-4 cm
0.75 μm =
Cross Multiply
= 0.75 μm × 1 × 10^-4 cm/ 1 μm
= 0.000075cm
Volume of the Sphere(Bacteria) = 4/3 × π × r³
= 4/3 × π × (0.000075)³
= 1.767145867 × 10^-12 cm³
Approximately as 2 significant figures = 1.8 × 10^-12 cm³
b) The formula for the Surface area of a Sphere = 4πr²
Diameter = 1.5 μm
Radius = Diameter/2 = 1.5μm/2
= 0.75μm
We are told that the surface area should be in square millimeters
Converting 0.75μm to millimeters
1 μm = 0.001 mm
0.75 μm =
Cross Multiply
= 0.75 μm ×0.001mm/ 1 μm
= 0.00075mm
Surface Area of a Sphere
= 4 × π × r²
= 4 × π × 0.00075²
= 7.06858 ×10^-6 mm²
Approximately to 2 significant figures
= 7.1 × 10^-6 mm²
Calculate the mean of this data set: 12, 35, 44, 74, 23, 49, 45, 18, 90, 56, 84,
Blababa [14]
Well, here is the mean of ur data collected 48.181818...
Answer:
f(- 2) = - 2
Step-by-step explanation:
To evaluate f(- 2) substitute x = - 2 into f(x)
f(- 2) = 3(- 2) + 4 = - 6 + 4 = - 2
Answer:
a = 
Step-by-step explanation:
Given:
f(x) = log(x)
and,
f(kaa) = kf(a)
now applying the given function, we get
⇒ log(kaa) = k × log(a)
or
⇒ log(ka²) = k × log(a)
Now, we know the property of the log function that
log(AB) = log(A) + log(B)
and,
log(Aᵇ) = b × log(A)
Thus,
⇒ log(k) + log(a²) = k × log(a) (using log(AB) = log(A) + log(B) )
or
⇒ log(k) + 2log(a) = k × log(a) (using log(Aᵇ) = b × log(A) )
or
⇒ k × log(a) - 2log(a) = log(k)
or
⇒ log(a) × (k - 2) = log(k)
or
⇒ log(a) = (k - 2)⁻¹ × log(k)
or
⇒ log(a) = 
(using log(Aᵇ) = b × log(A) )
taking anti-log both sides
⇒ a =
