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Pavlova-9 [17]
3 years ago
14

I Need HELP ASAP!!! Please help

Mathematics
1 answer:
NikAS [45]3 years ago
4 0

The answer is 407.5, it's an exponential decay function

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How many solutions does the following equation have? ln(x2 + 4x − 5) = 0
lisov135 [29]
Alrighty
remember
log_a(b)=c means a^c=b
and
ln(x)=log_e(x)
and
x^0=1 for all real values of x
so

ln(x^2+4x-5)=0 means
log_e(x^2+4x-5)=0 means
e^0=x^2+4x-5 which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square
x=-2+\sqrt{10} and x=-2-\sqrt{10}
2 solutions
7 0
3 years ago
Which expression is equivalent to that
kari74 [83]

Answer:

3. 9x

4. D. -5v + 4

Step-by-step explanation:

3. (-3+12)v

= 9v

4. Combine like terms:

(-2v - 3v) + (8 - 4)

= -5v + 4

6 0
4 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!
sergeinik [125]

Answer: 5.196152423

Step-by-step explanation: Logically considering it's a Rhombus all the sides are equal to each other. So you just need to find the area. In this case you find the area by multiplying the sin of the given angle by the square root of the given side. So, 6²×sin (60)=6²×√3/2=31.17691454. After finding the area you then have to divide the area by it's base to find the height. So, 31.17691454 ÷ 6 = 5.196152423.

I didn't round any of the numbers. Hopefully this is correct.

Sorry about the messy diagrams (never been good at creating them) and how long it took.

4 0
3 years ago
Read 2 more answers
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
2: A bag contains 5 black counters, 4 blue counters, and
drek231 [11]

Answer:

The probability that the counter  was blue is \mathbf{\frac{2}{5}}

Step-by-step explanation:

Number of black Counters = 5

Number of blue Counters = 4

Number of white Counters = 1

We need to write down the probability that the counter  was blue.​

First find Total Counters

Total Counters = Number of black Counters + Number of blue Counters + Number of white Counters

Total Counters = 5+4+1

Total Counters = 10

Now, we need to find probability that the counter taken was blue

The formula used is:

Probability= \frac{Number\:of\:favourable\:outcomes}{Total\:outcomes}

There are 4 blue counters in the back, so Favourable outcomes = 4

Probability= \frac{Number\:of\:favourable\:outcomes}{Total\:outcomes}\\Probability= \frac{4}{10}\\Probability= \frac{2}{5}

The probability that the counter  was blue is \mathbf{\frac{2}{5}}

5 0
3 years ago
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