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ANEK [815]
3 years ago
7

What are the constraints of mine shaft head gear​

Computers and Technology
1 answer:
Serhud [2]3 years ago
4 0

Answer:

Mine headgear constructions support wheel mechanisms for suspending winding cables that transport workers and ore up and down deep level shafts. These strange anthropomorphic structures have become the iconic symbol for mining.

You might be interested in
2. Input a decimal number and test if it is not equal to 16.5.
lubasha [3.4K]

Answer:

2:

decNum = float(input("Decimal number: "))

if decNum != 16.5:

   print("Does not equal")

elif decNum == 16.5:

   print("Equal")

else:

   pass

3:

if x > 57:

   x += 4

   print(x)

4:

numOne = int(input("Enter number: "))

numTwo = int(input("Enter number: "))

if numOne < 100 and numTwo < 100:

   yes = numOne + numTwo

   print(yes // 2)

else:

   pass

Explanation:

Please give me brainliest.

6 0
2 years ago
How can you use Word in order to edit and print documents ?
AleksandrR [38]

Answer:

in word, you go to the File tab on a document, then click print, or enter the keyboard shortcut: ctrl+p

to edit a downloaded document, open the document, and on the top of the document, click "enable editing"

Explanation:

hope this helps!

4 0
3 years ago
Everyone within a company needs to be aware of what data can do to improve business processes and how to make it happen. Which c
OLga [1]

The concept that is been referred to in the statement above is known as data literacy.

<h3>What is data literacy?</h3>

The term data literacy is known to be man's  ability to be able to read data, compose and share data. The  understanding of data sources and how it works it all about  data literacy.

Conclusively, when everyone in a firm are said to be data literate, There will be a lot of improvement in business processes of any firm.

Learn more about data literacy from

brainly.com/question/16514379

7 0
2 years ago
1. Name a two methods for creating text in Adobe Illustrator.
Fittoniya [83]

Answer:

Point type is a horizontal or vertical line of text that begins where you click and expands as you enter characters. Each line of text is independent—the line expands or shrinks as you edit it, but doesn’t wrap to the next line. Entering text this way is useful for adding a few words to your artwork.

Select the Type tool  or the Vertical Type tool .

The pointer changes to an I-beam within a dotted box. The small horizontal line near the bottom of the I-beam marks the position of the baseline, on which the text rests.

(Optional) Set text-formatting options in the Control panel, Character panel, or Paragraph panel.

Click where you want the line of text to begin.

Explanation:

4 0
3 years ago
Data Structure in C++
agasfer [191]

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

   

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

   

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

   

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

4 0
4 years ago
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