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alex41 [277]
3 years ago
10

5 / 4 x + 3 = x - 1 / 4

Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0
5/4x+3 = x-1/4
5/4x-x = -1/4-3
1/4x = -13/4
x = -13/4.4
x = - 13
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hichkok12 [17]
I believe it is biased
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3 years ago
The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times
almond37 [142]

Answer:

First angle = 30°

Second angle = 60°

Third angle = 90°

Step-by-step explanation:

x + y + z = 180

y + z = 5x

z = y + 30

then:

y + (y+30) = 5x

2y + 30 = 5x

x = (2y+30)/5

then:

x + y + z = 180

{(2y+30)/5} + y + y+30 = 180

{(2y+30)/5} + 2y + 30 = 180

{(2y+30)/5} = 180 - 30 - 2y

{(2y+30)/5} = 150 - 2y

2y+30 = 5(150-2y)

2y+30 = 5*150 + 5*-2y

2y+30 = 750 - 10y

2y + 10y = 750 - 30

12y = 720

y = 720/12

y = 60°

x = (2y+30)/5

x = (2*60 + 30)/5

x = (120+30)/5

x = 150/5

x = 30°

z = y + 30

z = 60 + 30

z = 90°

Check:

x + y + z = 180°

30° + 60° + 90° = 180°

7 0
3 years ago
4.
Simora [160]
M >= 85. The >= sign means greater than or equal to.
8 0
2 years ago
Annette is surveying people in the city about a new shopping mall. She found out that 180 people, or 37.5% of people do not want
Leokris [45]

Answer:

480 people

Step-by-step explanation:

Set up an equation where x is the number of people surveyed:

180 = (x)(0.375)

Solve for x:

180 = (x)(0.375)

480 = x

So, Annette surveyed 480 people

4 0
2 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
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