Subtract 2_5/8 minus 1_1/3:
First, get the fractions to have a common denominator by multiplying the denominators together: 8*3 = 24
Rewrite both fractions with this new denominator:
5/8 needs to be multiplied by 3 on top and bottom to make it have a denominator of 24:
5/8 * 3/3 = 15/24
1/3 needs to be multiplied by 8 on top and bottom to make it have a denominator of 24:
1/3 * 8/8 = 8/24
Now that the fractions have been rewritten with the same denominator, subtract the mixed numbers:
2_15/24 - 1_8/24
Whole numbers:
2 - 1 = 1
Fractions:
15/24 - 8/24 = 7/24.
The can of condensed soup contains 1_7/24 cup
9/10 or 0.9
Hope this helps
The elimination method is a sufficient way to solve problems.
2x+y= 20
6x-5y=12
Add 5y to the one equation.
2x+6y= 20
6x= 12
Subtract 2x from both sides.
6y= 20
4x= 12
Divide 6 by 20.
y= 3.3
Divide 4 by 12.
x= 3
I hope this helped you!
Brainliest answer is appreciated!
Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
