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mart [117]
2 years ago
8

Quadrilateral DEFG - quadrilateral KLMN. Find the given side length.

Mathematics
1 answer:
Delvig [45]2 years ago
3 0

Answer:

Step-by-step explanation:

By the diagram FG = MN.

3y + 3 = 5y - 25          Add 25 to both sides

3y + 3 + 25 = 5y         Subtract 3y from both sides

28 = 5y - 3y                Combine

28 = 2y                       Divide by 2

28/2 = 2y/2

y = 15

15 is not your answer. It is just the value of y.

3y + 3 = 3*15 + 3 = 45 + 3 = 48

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What is the radius of the circle given by the equation below?
lapo4ka [179]

Answer:

A. 3

Step-by-step explanation:

Hello

X^2 + 8X + (8/2)^2 + Y^2 + 14Y + (14/2)^2 = (8/2)^2 + (14/2)^2-56

(X+4)^2 + (Y+7)^2 = 16 + 49 - 56

(X+4)^2 + (Y+7)^2 = 9

Then

The radius for that circle is 3

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3 0
3 years ago
In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?
o-na [289]

Answer:

x = 25

Step-by-step explanation:

Correct question

In a right triangle Sin (40-x)=cos(3x) what is the value of x

Since Sin theta = Cos(90-theta)

Sin (40-x) = Sin(90-3x)

40 - x = 90 - 3x

-x+3x = 90 - 40

2x = 50

x = 25

Hence the value of x is 25

5 0
3 years ago
19. The temperatures at sunrise and sunset<br> are shown in the table
Likurg_2 [28]

The temperature change on the second day is greater than the temperature change on the first day.

<h3>What is temperature change?</h3>

The term temperature change refers to the difference in the temperature between the sunrise and the sunset. The temperature at sunrise and sunset are shown in the table attached to this answer.

The change in temperature on the first day is;

13.49 - (-11.31) = 24.80

The change in temperature on the second day is;

25.25 - (-7.69) = 32.94

Thus, the temperature change on the second day is greater than the temperature change on the first day.

Learn more about temperature change:brainly.com/question/11186605

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