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mart [117]
2 years ago
8

Quadrilateral DEFG - quadrilateral KLMN. Find the given side length.

Mathematics
1 answer:
Delvig [45]2 years ago
3 0

Answer:

Step-by-step explanation:

By the diagram FG = MN.

3y + 3 = 5y - 25          Add 25 to both sides

3y + 3 + 25 = 5y         Subtract 3y from both sides

28 = 5y - 3y                Combine

28 = 2y                       Divide by 2

28/2 = 2y/2

y = 15

15 is not your answer. It is just the value of y.

3y + 3 = 3*15 + 3 = 45 + 3 = 48

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Given that p=9i+12j and q=-6i-8j. Evaluate |p-q|-{|p|-|q|}
krok68 [10]

Answer:

|p-q|-(|p|-|q|) = 20

Step-by-step explanation:

First let's find the value of 'p-q':

p - q = 9i + 12j - (-6i - 8j)\\p - q = 9i + 12j + 6i + 8j\\p - q = 15i + 20j\\

To find |p-q| (module of 'p-q'), we can use the formula:

|ai + bj| = \sqrt{a^{2}+b^{2}}

Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'

So we have:

|p - q| = |15i + 20j| = \sqrt{15^{2}+20^{2}} = 25

Now, we need to find the module of p and the module of q:|p| = |9i + 12j| = \sqrt{9^{2}+12^{2}} = 15

|q| = |-6i - 8j| = \sqrt{(-6)^{2}+(-8)^{2}} = 10

Then, evaluating |p-q|-{|p|-|q|}, we have:

|p-q|-(|p|-|q|) = 25 - (15 - 10) = 25 - 5 = 20

7 0
3 years ago
Solve<br> x2 - 8x + 14 = 2x - 7
BabaBlast [244]

Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
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Tpy6a [65]

Answer:

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Step-by-step explanation:

19/13-5/13=14/13

Since the denominators are the same, you just do the subtraction of the nominators.

3 0
3 years ago
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<span>f(x) = x² + 4x
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