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ivolga24 [154]
3 years ago
13

How many terms are there in a geometric series if the first terms is 2, the common ratio is 4, and the sum of the series is 2,73

0 ?
Mathematics
1 answer:
arsen [322]3 years ago
4 0
The sum of n terms of a geometric series is given by
S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}

Substituting the given numbers, you have
2730=2\dfrac{4^{n}-1}{4-1}\\\\2730\dfrac{3}{2}=4^{n}-1\\\\4096=4^{n}\\\\\dfrac{\log(4096)}{\log(4)}=n=6

There are 6 terms in the series.
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Read 2 more answers
How do I solve this?
pishuonlain [190]
Good morning! So, what this question wants us to do is find each y value given its x value. Without the function it gives us already, this would be pretty difficult.
It gives us a function rule of y=2x+3. This means that we need to plug in each x value into the equation and solve for y. Let’s work on these first three.

y=2x+3} x=-4
y=2(-4)+3
y=-8+3
y=-5
So, if x=-4, then y=-5.

y=2x+3} x=-2
y=2(-2)+3
y=-4+3
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So, if x=-4, then y=-1.

y=2x+3} x=0
y=2(0)+3
y=0+3
y=3
So, if x=0, then y=3.

Try out the last one, and if you have any questions, comment below! Here are some extra x values if you need more practice.
Using the same function rule, y=2x+3, try to find the y value if x=-6, x=-3, x=5, or x=6.
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Y'all help a bestie out
My name is Ann [436]

Answer:

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