|DF| = |DE| + |EF| |DF| = 9x -36 |DE| = 47 |EF| = 3x+10 Substitute: 9x - 39 = 47 + 3x + 10 9x - 39 = 3x + 57 |+39 9x = 3x + 96 |-3x 6x = 96 |:6 x = 16 Put the value of x to the equation |EF| = 3x + 10 |EF| = (3)(16) + 10 = 48 + 10 = 58 Answer: |EF| = 58
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It would be log7squared(7)
The answer is 6
hope this helped
Answer:
0.25
Step-by-step explanation:
Answer:
1,250 lbs
Step-by-step explanation:
There are 2,000 in 1 ton, so 5 * 2,000 = 10,000 lbs weight limit for the bridge.
10,000-8750 = 1,250 lbs can be added to the truck before they reach the bridge weight limit.
