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3 years ago

Choose the most specific description of a curve that is a subset of a circle.

2 answers:

8 0

I would say it's arc providing the curve possesses a constant rate of curvature.

And the curve by definition follows the rule.

Maksim231197 [3]3 years ago

7 0

Arc. an arc is a curve that is subset of a circle

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How do you simplify 4/5

Sladkaya [172]

4/5 is in its simplest form.

8 0

3 years ago

Read 2 more answers

Suppose Sally has 9.94 kilograms of seed. If it takes 7.1 kilograms of seed to plant one hectare of land, how many hectares of l

Andrew [12]

Answer:

9.94 kg seed need 1.4 hectare of land

Step-by-step explanation:

Sally has=9.94kg

1 hectar need=7.1 kg

Now,

9.94kg=(9.94/7.1) hectare

=1.4 hectare

so,9.94 kg =1.4 hectare

6 0

3 years ago

PLS HELP AM I RIGHT!!!!? IF NOT PLEASE TELL ME AND SHOW YOUR WORK FOR 10 POINTS

Salsk061 [2.6K]

Answer:

you are correct

Step-by-step explanation:

since there is a box in the angle, it means it's 90°, so if the 1rst angle is 30°, the other one has to be 60°

5 0

3 years ago

Richard wants to make a garden with a perimeter of 16 feet, and length of 4 feet. He solves for the width by subtracting 8 from

Ostrovityanka [42]

The equation that can be used to solve this is:

$P =2W+2L\\OR\\P-2L = 2W\\\frac{P-2L}{2} = W$

Further explanation:

Let

$P\ be\ the\ perimeter\\L\ be\ the\ width\\W\ be\ the\ width$

The equation for the perimeter will be:

$P =2W+2L$

Given

P = 16 feet

L = 4 feet

W = ?

Putting the values in the perimeter formula

$16=2(4)+2W\\16=8+2W\\16-8= 2L\\8=2L\\L=\frac{8}{2}\\L=4\ feet$

The equation that can be used to solve this is:

$P =2W+2L\\OR\\P-2L = 2W\\\frac{P-2L}{2} = W$

Keywords: Periemter of rectangle, linear equation

Learn more about perimeter of rectangle at:

#LearnwithBrainly

3 0

3 years ago

Write the standard form of an equation of an ellipse subject to the given conditions.

irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

$\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1$

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

$\frac{x^2}{1369}+ \frac{y^2}{1394} =1$

6 0

3 years ago