Answer:
The combined cost of one loaf of bread and one package of cheese is $6.5
Step-by-step explanation:
Given :
Mason bought 6 loaves of bread and 3 packages of cheese for a total of $27.
The cost of a package of cheese is $1.50 more than the cost of a one loaf of bread.
To Find :The combined cost of one loaf of bread and one package of cheese.
Solution :
Let cost of one loaf of bread is $x.
Cost of 6 loaves of bread = $6x.
Let cost of one package of cheese is $y.
Cost of 3 packages of cheese = $3y.
Since we are given that combined cost of 6 loaves of bread and 3 packages of cheese is $27.
⇒ 6x + 3y = 27 ----(A)
We are also given that the cost of a package of cheese is $1.50 more than the cost of a one loaf of bread.
⇒y = x + 1.50 ----(B)
Solving (A) and (B) using substitution method
Substitute value of y from (B) in (A)
⇒6x + 3(x + 1.50 ) = 27
⇒6x +3x +4.5 = 27
⇒9x + 4.5 = 27
⇒9x = 27-4.5
⇒9x = 22.5
⇒x = 22.5/9
⇒x = 2.5
Thus, The cost of one loaf of bread 'x' = $2.5
Substitute this value of x in (B) to get cost of one package of cheese 'y'
⇒y =2.5 + 1.50
⇒ y = 4
Thus, The cost of one package of cheese 'y' = $4
Thus the combined cost of one loaf of bread and one package of cheese i.e. x + y = $2.5+$4 =$6.5
Hence , The combined cost of one loaf of bread and one package of cheese is $6.5
