The equation of a circle is:
(x-h)2 + (y-k)2 = r2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2
r= 10
The final equation is:
(x-5)2 + (y+4)2 = 102
Answer:
number of math cpurses: discrete. weight of backpacks: continuous
Step-by-step explanation:
The measure of angle 6 is 84 :)
The place where two equations intersect, has a certain value of y. This means that in the intersection point, the y-values of both expressions are the same, so y = y. Since y is also represented by the following equations, y = 4x and y = 2x - 2, the x-value of the intersection point is 4x = 2x - 2.
Answer:
a and c
Step-by-step explanation:
7(4)-1 =27
9(4)+22 does not equal 26
46-8(4)=14
5(4)+40 does not equal 62
