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hjlf
3 years ago
9

Help please !!!!!!! Thanks in advance

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
I got u c is 90 degree angle and a is a 45 degree angle so then you add that up and get 135
Rudik [331]3 years ago
3 0

Answer:

Sorry, the question doesn't make sense. But Measure of angle A is28 degrees. what are you trying to figure out for just A and C?

Step-by-step explanation:

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Please answer this question if you are correct i will mark brainliest
bekas [8.4K]

Step-by-step explanation:

Since there are 4 people who answered that they had 0 number of scarves we put 4 0's in a set of numbers. Then we see that there are 2 people who have 1 scarf. so there are 2 1's and we keep on going down the line.

{0,0,0,0,1,1,2,3,3,4,5,5} there are 12 numbers here

so we add up all of them

1+1+2+3+3+4+5+5=24

then divide that number by 12 because that's how many numbers there are

24/12=2

The mean of the numbers is 2

Hope that helps :)

5 0
3 years ago
A recent survey found that 79% of Americans use the internet. if a city has a population of 76,000 how many people in that city
Nuetrik [128]
p\%=\frac{p}{100}\\\\79\%=\frac{79}{100}=0.79\\\\79\%\ of\ 76,000\ is\ 0.79\ \times\ 76,000=60,040\leftarrow answer
3 0
3 years ago
Read 2 more answers
The square of nine less than a number is three less than the number. What is the number ?
kvv77 [185]
Let n represent the number.
.. (n -9)^2 = n -3 . . . . . the square of 9 less than the number is 3 less than the number
.. n^2 -18n +81 = n -3
.. n^2 -19n +84 = 0
.. (n -7)(n -12) = 0
.. n = 7 or 12

The number could be 7 or 12.


_____
Check:
.. (7 -9)^2 = (-2)^2 = 4 = 7 -3 . . . . answer checks OK
.. (12 -9)^2 = 3^2 = 9 = 12 -3 . . . . answer checks OK
3 0
3 years ago
Match the following equation to the correct situation.
nevsk [136]

Answer:

b

Step-by-step explanation:

Say Jess owes 30 dollars

30 + 3(.05) = 31.5

30(1.05= 31.5

it makes a lot of sense

7 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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