Answer:
(x+1)(2x+5)
Step-by-step explanation:
f(x) = 2x² + 7x + 5
Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.
a+b=7
ab=2×5=10
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.
1,10
2,5
Calculate the sum for each pair.
1+10=11
2+5=7
The solution is the pair that gives sum 7.
a=2
b=5
2x²+7x+5 as (2x²+2x)+(5x+5).
(2x²+2x)+(5x+5)
Factor out 2x in the first and 5 in the second group.
2x(x+1)+5(x+1)
Factor out common term x+1 by using distributive property.
(x+1)(2x+5)
Answer:
-2.453
Step-by-step explanation:
sqrt(6) * sqrt(2) = 3.461
sqrt(6) * -2 = -4.899
sqrt(3) * sqrt(2) = 2.449
sqrt(3) * -2 = -3.464
sum of numbers equals
-2.453
1/5.
If 4 pieces of gum are each divided into 5 parts, that will mean there will be 20 smaller parts (5*4=20).
Each person will get one part of each piece of gum. If there are 4 pieces of gum originally, this means each person gets 4 small pieces of gum
If each person gets 4 small pieces of gum and there are 20 small pieces altogether, that makes the fraction 4/20
Since 4 and 20 are both divisible by 4, that makes the simplified answer 1/5.
Hello,
first we have to descompose the number:
128 | 2
64 | 2
32 | 2
16 | 2
8 | 2
4 | 2
2 | 2
1
So:
Therefore:
You must know these properties:
![\sqrt{a*b} = \sqrt{a} * \sqrt{b}\\ \\ \sqrt[b]{x^a}= x^{ \frac{a}{b}}](https://tex.z-dn.net/?f=%20%5Csqrt%7Ba%2Ab%7D%20%3D%20%5Csqrt%7Ba%7D%20%2A%20%5Csqrt%7Bb%7D%5C%5C%20%5C%5C%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D%3D%20x%5E%7B%20%5Cfrac%7Ba%7D%7Bb%7D%7D%20)
then:
