Answer:
C
Step-by-step explanation:
The answer is C, because an element of the sample space for tossing a coin would be either Heads (H) or Tails (T).
And an element of the sample space for rolling a die would be a number between 1-6, all inclusive.
Answer:
dC =0.6899T + 30.02
dC/C = (0.6899T + 30.02)/(35.74 + 0.6215T - 35.75V^0.16 + 0.4275Tv^0.16
Step-by-step explanation:
C= 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16
dC = 35.74 + 0.6215T - (35.75×0.16) +:(0.4275×0.16)
dC = 35.74 + 0.6215T - 5.72 + 0.684T
dC = 0.6899T + 30.02
dC/C = (0.6899 + 30.02)/(35.74 + 0.6215T - 35.75Tv^0.16 + 0.4275Tv^0.16
A confidence interval for the true mean SAT score of the graduating high school seniors will be (496; 536)
<h3>What is a confidence interval?</h3>
A confidence interval (CI) is a range of estimates for an unknown parameter in frequentist statistics.
Mean score ± margin of error
Margin of Error = 20
Mean SAT score = 516
Hence,the confidence interval will be:-
= 516 ± 20
Lower boundary = 516 - 20 = 496
Upper boundary = 516 + 20 = 536
To know more about confidence intervals follow
brainly.com/question/16974109
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Answer:
-2
Step-by-step explanation:
