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3 years ago

A ceramic vase that cost an antique store $5 was marked $20. what is the percentage markup on the price of the ceramic vase?

Mathematics

1 answer:

VikaD [51]3 years ago

3 0

20/25 × 10% = 80%

the answer is 80%

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Billy is hiking in Colorado. He walks eastward four miles, then turns $60$ degrees northward and walks six miles. How far is he

nikklg [1K]

He is 2√19 miles far way from starting point.

Suppose Billy starts at point A, turns at point B, and ends at point D, as shown below.

If Billy turns 60◦ northward and walks six miles, then we can draw a 30 − 60 − 90 triangle whose hypotenuse is 6 miles

It follows that Billy traveled 6/2 = 3 miles eastward during these 6 miles, and that he traveled 3√3 miles northward during these 6 miles. In total, Billy traveled 4 + 3 = 7 miles eastward and 3√ 3 miles northward.

By the Pythagorean Theorem, the distance from his starting point is q:

(7)2 + (3√3)2

=√49 + 27

= √76

= 2√19 .

Learn more about Pythagorean Theorem on:

brainly.com/question/20545047

#SPJ4

5 0

2 years ago

32/160 as a simplified fraction someone help coz I'm clueless with fractions

omeli [17]

32÷2/160÷2

=16÷2/80÷2

8÷2/40÷2

4÷2/20÷2

2÷2/10÷2

1/5

4 0

3 years ago

Read 2 more answers

36/45 reduced in the lowest terms

malfutka [58]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

They both (36 and 45) go into 9. Divide them both by 9.

$\frac{4}5}$

6 0

3 years ago

Read 2 more answers

LING'S HALLWAY IS 10 FEET LONG AND 4 FEET WIDE. HE PAID $200 TO TILE HIS HALLWAY FLOOR. HOW MUCH DID LING PAY PER SQUARE FOOT FO

ivanzaharov [21]

Answer:

Step-by-step explanation:

10x4/200=5

5 0

3 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

4 0

3 years ago