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Artyom0805 [142]
2 years ago
8

If a triangle is an isosceles triangle, then it has two sides of equal length. If a triangle has two sides of equal length, then

it has two angles of equal measure
Conclusion:
If a triangle is an isosceles triangle, then it has two angles of equal measure.



The argument is not valid because the conclusion does not follow from the premises.

The argument is valid by the law of syllogism.

The argument is not valid because the premises are not true.

The argument is valid by the law of detachment.
Mathematics
2 answers:
ivann1987 [24]2 years ago
8 0

we know that

<u>The Law of Syllogism</u> says that if the following two statements are true:

(1) If p -------> then q .

(2) If q-------> then r .

Then we can derive a third true statement:

(3) If p--------> then r .

In this problem

(1) If a triangle is an isosceles triangle, then it has two sides of equal length

(2) If a triangle has two sides of equal length, then it has two angles of equal measure

Let

p-------> the statement " an isosceles triangle"

q--------> the statement " has two sides of equal length"

r--------->  the statement "has two angles of equal measure"

Then (1) and (2) can be written

1) If p , then q .

2) If q , then r .

So, by the Law of Syllogism, we can deduce

3) If p , then r

or

If a triangle is an isosceles triangle, has two angles of equal measure

therefore

<u>the answer is</u>

The argument is valid by the law of syllogism.

Ann [662]2 years ago
3 0
It is valid through syllogism

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The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area
miv72 [106K]

Answer:

20 square feet

Step-by-step explanation:

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Step 1

We find the Length and Width of the deck

Perimeter of a rectangle = 2L + 2W

The length of a rectangular deck is five times it's width

W = Width

L = Length = 5W

P = 24 feet

Perimeter = 2(5W) + 2W

24 = 10W + 2W

24 = 12 W

W = 24/12

W = 2 feet

Solving for L

L = 5W

L = 5 × 2 feet

L = 10 feet

Step 2

We find the area of the deck

Area of the deck(Rectangle) = Length × Width

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