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Artyom0805 [142]
3 years ago
8

If a triangle is an isosceles triangle, then it has two sides of equal length. If a triangle has two sides of equal length, then

it has two angles of equal measure
Conclusion:
If a triangle is an isosceles triangle, then it has two angles of equal measure.



The argument is not valid because the conclusion does not follow from the premises.

The argument is valid by the law of syllogism.

The argument is not valid because the premises are not true.

The argument is valid by the law of detachment.
Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0

we know that

<u>The Law of Syllogism</u> says that if the following two statements are true:

(1) If p -------> then q .

(2) If q-------> then r .

Then we can derive a third true statement:

(3) If p--------> then r .

In this problem

(1) If a triangle is an isosceles triangle, then it has two sides of equal length

(2) If a triangle has two sides of equal length, then it has two angles of equal measure

Let

p-------> the statement " an isosceles triangle"

q--------> the statement " has two sides of equal length"

r--------->  the statement "has two angles of equal measure"

Then (1) and (2) can be written

1) If p , then q .

2) If q , then r .

So, by the Law of Syllogism, we can deduce

3) If p , then r

or

If a triangle is an isosceles triangle, has two angles of equal measure

therefore

<u>the answer is</u>

The argument is valid by the law of syllogism.

Ann [662]3 years ago
3 0
It is valid through syllogism

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The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is \bar x =\frac{1}{n}  \sum X_i where n is the number of observations; X_i are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is \bar x = \frac{1}{N}\sum f_ix_i where N =\sum f_i and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is m_e = 14.99, and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations x_i and frequencies f_i.

Then, the mean is calculated by

\bar x = \frac{1}{N}\sum f_ix_i

Where N =\sum f_i (Sum of frequencies)

The median is calculated by

m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

\bar x =\frac{1}{n}  \sum X_i

Where n = 25; X_i - n observations

On substituting,

Mean \bar x

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

\bar x = \frac{1}{N}\sum f_ix_i

Where N = 25;

On substituting,

\bar x<em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

  = 1/25 (402.42)

  = 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So,  the median m_e = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

#SPJ9

7 0
2 years ago
DOES ANYONE KNOW THE ANSWER?????????
givi [52]

There's only information to answer question C.

We can only know that 32 marbles were chosen. (yellow and black)

Why?

To answer the first two questions (a and b), we need to know the total number of marbles, so, we can only answer the last question (c).

We know that 7/10 of the 20 yellow marbles were chosen.

So, calculating we have:

\frac{7}{10}*20=14(yellow)

Also, we know that 18 black marbles were chosen, so, the total of marbles chosen is equal to 32 (yellow marbles and black marbles)

TotalMarbles=14(yellow)+18(black)=32marbles

Have a nice day!

8 0
3 years ago
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