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Artyom0805 [142]
3 years ago
8

If a triangle is an isosceles triangle, then it has two sides of equal length. If a triangle has two sides of equal length, then

it has two angles of equal measure
Conclusion:
If a triangle is an isosceles triangle, then it has two angles of equal measure.



The argument is not valid because the conclusion does not follow from the premises.

The argument is valid by the law of syllogism.

The argument is not valid because the premises are not true.

The argument is valid by the law of detachment.
Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0

we know that

<u>The Law of Syllogism</u> says that if the following two statements are true:

(1) If p -------> then q .

(2) If q-------> then r .

Then we can derive a third true statement:

(3) If p--------> then r .

In this problem

(1) If a triangle is an isosceles triangle, then it has two sides of equal length

(2) If a triangle has two sides of equal length, then it has two angles of equal measure

Let

p-------> the statement " an isosceles triangle"

q--------> the statement " has two sides of equal length"

r--------->  the statement "has two angles of equal measure"

Then (1) and (2) can be written

1) If p , then q .

2) If q , then r .

So, by the Law of Syllogism, we can deduce

3) If p , then r

or

If a triangle is an isosceles triangle, has two angles of equal measure

therefore

<u>the answer is</u>

The argument is valid by the law of syllogism.

Ann [662]3 years ago
3 0
It is valid through syllogism

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kap26 [50]
You have to break up 384 into numbers that can be taken out to the radical.

You can break up 384 into 2^3*2^3*6.

Since two 2’s can be taken you would have 4 on the outside and a 6 and x^4 left on the inside.

x^3 can be taken out, leaving an x inside the radical.

The final answer would be 4x on the outside and 6x left under the cubed radical

5 0
4 years ago
An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t
ratelena [41]

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

h(t)=96t-16t^2

a.h(t)=144 ft

144=96t-16t^2

16t^2-96t+144=0

t^2-6t+9=0

t^2-3t-3t+9=0

t(t-3)-3(t-3)=0

(t-3)(t-3)=0

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

96t-16t^2=0

16t(6-t)=0

16t=0\implies t=0

6-t=0\implies t=6

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.

6 0
3 years ago
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enot [183]

Answer:

i don't know but I think question 1 is 64

3 0
3 years ago
The midpoint (x, y) and the end point (x2, y2) are known. Find (x1, Y1) using the midpoint formula.
FrozenT [24]

Answer:

(x1,y1) = (2x - x2, 2y - y2)

Step-by-step explanation:

Given:

Midpoint = (x , y)

End point = (x2, y2)

Find:

(x1, y1)

Computation:

Mid-point formula

x = (x1 + x2) / 2 , y = (y1 + y2) / 2

So,

2x = x1 + x2 , 2y = y1 + y2

x1 = 2x - x2 , y1 = 2y - y2

So,

(x1,y1) = (2x - x2, 2y - y2)

3 0
3 years ago
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10.
1/2 and 3/5 have the denominators 2 and 5. The smallest number that both 2 and 5 can go into is 10.
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