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irga5000 [103]
3 years ago
11

If a student didnt turn an assignment in on the 27th of august, and the teacher deducted 10 percent each day. How much credit wo

uld they get if they turned it in on the 1st of september?
Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

i have no idea

Step-by-step explanation:

nirvana33 [79]3 years ago
7 0

Answer:

credit of 60= lost 40  points

Step-by-step explanation:

31-27= 4

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Expand the following:<br> 3/8 (16x - 24)<br> Please help me
tresset_1 [31]

Answer:

48x-6

Step-by-step explanation:

3(16x-24)/8

48x-72/8

48x-6

6 0
3 years ago
Help quik
artcher [175]
The answer will be 1/40
4 0
4 years ago
Read 2 more answers
Factor the expression.<br> x squared-25
grin007 [14]
X2<span> - 25 = x</span>2<span> - 5</span>2<span> = (x - 5)(x + 5)

</span>
4 0
4 years ago
What is the value of p so that the expression 6x+3−(8x−5) is equivalent to (px+8) ?
Harman [31]
6x+3-(8x-5)
=
-2x(x-4)
=
2x+8
=
p = 2
8 0
3 years ago
A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn
tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range


(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)


The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.


The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:


\sigma = \dfrac{ 11}{\sqrt{121}} = 1


So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range


(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)


That's probably the answer they're looking for.



4 0
3 years ago
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