Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
Answer:
5x + 3y - 4
This expression has three terms (5x, 3y, and -4), 2 different variables (x and y), and a constant (-4)
Step-by-step explanation:
#teamtrees #WAP (Water And Plant)
Answer:
A) -3/2 and 7
Step-by-step explanation:
this equation factors to (2x+3)(x-7)
the goal is to solve for 0
if 2x+3=0 then x=-3/2
if x-7=0 then x=7
Answer:
Step-by-step explanation:
a 2m+5=13
2m=8
m=4
b 3m/5=-6
3m=-30
m=-10
c 4-5x=19
-5x=15
x=-3
d x/4-10=2
x=48
e -24=8(h+3)
-24=8h+24
-48=8h
h=-6
f -3+d/2=9
-3+d=18
d=21
The volume of the prism ... L x W x H ... is 0.04 of the volume of the tank.
If the prism is rectangular, then its width is (0.04 of the volume of the tank) divided by (L x H of the prism) .
