Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!
Answer:
Yes
Step-by-step explanation:
Yes
because we are given that
LN ≅ XZ ( side)
the picture shows that
LM ≅XY ( side)
and
MN ≅ YZ (side)
By the <u>SSS theorem of congruency</u> we conclude that ΔLMN ≅ ΔXYZ
Answer:
64
Step-by-step explanation:
$346/100=$3.46 =1% of $346. So, giving 10% discount we $3.46*90=$311.40
Again, $311.40/100=$3.114, providing, 10% discount we get $3.114*90=$280.26.
The net cost after the series discount is $280.26
I hope this helps you
70=?.25%
70=?.25/100
70=?.1/4
?=280
