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inna [77]
3 years ago
13

Boys to girl 11;9 there are 124 more boys what is the total number of students

Mathematics
1 answer:
Deffense [45]3 years ago
7 0

(124 \div 2) \times (11 + 9) = 1240
total number of students : 1240
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PLZ HELP 70 POINTS!!!!!
marin [14]

5^(x+7)=(1/625)^(2x-13)


We move all terms to the left:


5^(x+7)-((1/625)^(2x-13))=0



Domain of the equation: 625)^(2x-13))!=0


x∈R



We add all the numbers together, and all the variables


5^(x+7)-((+1/625)^(2x-13))=0


We multiply all the terms by the denominator



(5^(x+7))*625)^(2x+1-13))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x-12))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x=0

not sure if this is right :/


8 0
3 years ago
Read 2 more answers
Lf R(x) = x2 – 3x – 1, find R(-2).<br><br> a.9<br> b.-9<br> c.-3<br> d.-11
fenix001 [56]

Answer:

A.

Step-by-step explanation:

If R(-2), then x = -2. Just plug in -2 for x. -2^2 - 3(-2) - 1 = 4 + 6 - 1 = 10 - 1 = 9. The answer is 9.

6 0
2 years ago
Please help thanks !
Kitty [74]

Answer:

option D

Step-by-step explanation:

x^{2} + y^{2} = 16\\\\x^{2} = 16- y^{2}

equation 2:

\frac{x^{2}}{4} - \frac{y^{2}}{25} = 1

so we have:

\frac{16- y^{2} }{4}-\frac{y^{2}}{25}= 1

7 0
3 years ago
The school sold $6000 worth of tickets. Adult tickets were seven dollar and children’s tickets were three dollars. Three times a
padilas [110]

Answer:

1,500 tickets in total (375 adult tickets and 1,125 children tickets)

Step-by-step explanation:

Let x be the number of adult tickets sold.

Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.

Children tickets were three dollars, so 3x children tickets cost \$3\cdot 3x=\$9x.

Adult tickets were seven dollar, so x adult tickets cost \$7\cdot x=\$7x.

The school sold $6000 worth of tickets.

Hence,

9x+7x=6,000\\ \\16x=6,000\\ \\x=\dfrac{6,000}{16}=375\\ \\3x=1,125\\ \\x+3x=375+1,125=1,500

7 0
3 years ago
determine the equation of the straight line which passes through the point 1 and 5 and is perpendicular to the line 3x + y is eq
xenn [34]

The straight line is perpendicular to y = -3x + 4.

Therefore, the gradient of the straight line must be 3.

The equation of the straight line is y = 3x + 2.

7 0
3 years ago
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