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iren [92.7K]
2 years ago
13

Methane (CH4) is a gas that is found in small quantities in Earth’s atmosphere. Which type of bonds does methane have, and why d

oes one carbon atom bond with four hydrogen atoms? In three to five sentences, explain your answer in terms of valence electrons and electronegativity.
Chemistry
1 answer:
katrin2010 [14]2 years ago
8 0

\huge\fcolorbox{red}{lightgreen}{Answer}

  • <u>Methane</u><u> </u><u>have</u><u> </u><u>4</u><u> </u><u>covalent</u><u> </u><u>bond</u><u>.</u><u> </u>
  • <u>One</u><u> </u><u>carbon</u><u> </u><u>form</u><u> </u><u>bond</u><u> </u><u>with</u><u> </u><u>4</u><u> </u><u>hydrogen</u><u> </u><u>bond</u><u> </u><u>because</u><u> </u><u>carbon</u><u> </u><u>need</u><u> </u><u>4</u><u> </u><u>valence</u><u> </u><u>electron</u><u> </u><u>to</u><u> </u><u>complete</u><u> </u><u>it's</u><u> </u><u>octet</u><u>.</u><u> </u>
  • <u>Carbon</u><u> </u><u>has</u><u> </u><u>4</u><u> </u><u>valence</u><u> </u><u>electron</u><u>.</u><u> </u><u>It</u><u> </u><u>need</u><u> </u><u>4</u><u> </u><u>electron</u><u> </u><u>to</u><u> </u><u>complete</u><u> </u><u>it's</u><u> </u><u>octet</u><u> </u><u>so</u><u> </u><u>it</u><u> </u><u>form</u><u> </u><u>bond</u><u> </u><u>with</u><u> </u><u>4</u><u> </u><u>hydrogen</u><u> </u><u>bond</u><u>.</u><u>And</u><u> </u><u>hydrogen</u><u> </u><u>has</u><u> </u><u>1</u><u> </u><u>valance</u><u> </u><u>electron</u><u> </u><u>so</u><u> </u><u>they</u><u> </u><u>easily</u><u> </u><u>complete</u><u> </u><u>the</u><u> </u><u>octet</u><u> </u><u>and</u><u> </u><u>form</u><u> </u><u>covalent</u><u> </u><u>bond</u><u>.</u><u> </u>
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7.) A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To
marysya [2.9K]

Answer:

T₂ = 721 k

Explanation:

Given data:

Initial volume = 285 mL

Initial pressure = 1.88 atm

Initial temperature = 355 K

Final temperature = ?

Final volume = 435 mL

Final pressure = 2.50 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  =  P₂V₂ T₁  / P₁V₁

T₂ = 2.50 atm × 435 mL × 355 K / 1.88 atm × 285 mL  

T₂ = 386062.5 atm. mL. K /535.8 atm. mL

T₂ = 721 k

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