Answer:
The answer to your question is the third option, atoms of each lose one electron to achieve stability.
Explanation:
a) The first option is incorrect, those elements are extremely reactive and can explode.
b) The option is also incorrect, metalloids are located in groups 3A, 4A OR 5A in the periodic table.
c) This option is correct
d) These elements have 1 valence electron, this option is wrong.
We have to calculate the number of carbon atoms present in 2-carat pure diamond.
The number of carbon atoms present in 2-carat pure diamond is: 0.19 X 10²³ number of carbon atom.
Diamond is one allotrope of carbon. Atomic mass of carbon is 12.
Mass of one mole carbon atom is 12 g. One mole carbon contains Avogadro's number i.e, 6.023 X 10²³ number of atoms.
0.40 g diamond contains 0.40/12 moles= 0.033 moles of carbon atom.
So, number of carbon atoms present in 0.40 g diamond (i.e, 0.033 mole diamond) is 0.033 X 6.023 X 10²³= 1.98 X 10²²=0.19 X 10²³ .
Therefore, 0.19 X 10²³ number of carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g
In the Bohr's Model of the atom, the protons are located in the nucleus. The electrons move around the nucleus. I hope this helps in some way. (:
