it's Lithium or Li
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Answer:
Maximum number of moles of AlCl3 produced is 5 moles
Explanation:
First thing's first, let's bring out the balanced chemical equation.
2Al + 3Cl2 -> 2AlCl3
Before proceeding to calculating the maximum number of moles of AlCl3 that can be formed, we have to identify the limiting reagent.
Every 2 mole of AlCl3 requires 2 moles of Al and 3 moles of Cl2.
If all of the 5 moles of Al were to be used up, there would need to be 5 × (2 / 3) or 3.333 moles of Cl2. 6 moles of Cl2 is available, this means Al is our limiting reagent.
5 mol of Al * (2 mol of Cl2 / 3 mol of Al) = 3.33 mol of Cl2
From the equation, 2 mol of Al produces 2 mol of AlCl3. This means 5 mol of Al would produce x?
2 = 2
5 = x
x = (5 * 2 ) / 2
x = 10 /2 = 5
Maximum number of moles of AlCl3 produced is 5 moles
Answer:
Friction, tension, air resistance requires physical contact .
Answer: 350 kJ/molExplanation:1) <span>δh = -250 kj/mol means that the products of the forward reaction are 250 kJ/mol lower in the potential enery diagram.
2) So, the reverse reaction must compensate the 250 kJ/mol and go upper as much as the activation energy of the forward reaction.
This is:
Ea reverse = Ea forward + | </span><span>
δh |You can see this clearer on the attached graph of an exothermic reaction.
Ea reverse = 100 kJ / mol + | -250 kJ/mol | = 100 kJ/mol + 250 kJ/mol = 350 kJ/mol
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Answer: V = 5.1 L
Explanation: To find the new volume, we will use the formula of Combined Gas Law and derive V2. We also need to convert first the temperature in Kelvin and convert torr to atm ( 1 atm = 760 torrs ).
Solution attached.