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2 years ago

Which of the following was a critique of the child-saving movement?

Mathematics

1 answer:

lord [1]2 years ago

6 0

Answer:

Critics said it caused more children to roam the streets. pls mark me branilest

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Solve y over negative 2 5 = 13.

devlian [24]

Y/-2 + 5 = 13
y/-2 = 13 - 5 = 8
y = -2(8) = -16
y = -16

8 0

2 years ago

Read 2 more answers

A is a prorportional three dimensional model of an object

klio [65]

Scale factor mark brainliest plz

5 0

2 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago

Graph the image of rhombus EFGH after a reflection across the line x = 3

igomit [66]

Answer: see image

<u>Step-by-step explanation:</u>

Draw line x = 3. Count how many units each point is away from line x = 3. Plot the new point the same number of units away from line x = 3 but in the opposite direction.

Point G is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.

Point F is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.

Point E is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.

Point H is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.

8 0

3 years ago

What’s this answer ? will give ton of points!!!!!!!!!!

Ann [662]

Answer:

268 cm^2

Step-by-step explanation:

Pink prism:

top: 2 cm * 2 cm = 4 cm^2

right, left, back, front: 4 * 2 cm * 6 cm = 48 cm^2

bottom: completely covered in connection to green prism

Total surface area of pink: 52 cm^2

Green prism:

bottom: 10 cm * 5 cm = 50 cm^2

front, back: 2 * 10 cm * 4 cm = 80 cm^2

right, left: 2 * 5 cm * 4 cm = 40 cm^2

top: 10 cm * 5 cm - 2 cm * 2 cm = 46 cm^2

Total surface area of green: 216 cm^2

Total surface area of composite solid:

52 cm^2 + 216 cm^2 = 268 cm^2

3 0

2 years ago