Answer:
GO STUDY!
Step-by-step explanation:
Good Luck!
Answer:
The function f(x) is not given, I used a different function but the approach and steps is the same .
Step-by-step explanation:
- Given the function f(x) = 2x2 - 8x + 5
compare with the normal quadratic equation ; ax2 + bx + c = f(x)
- since a is greater than zero i.e a > o {positive}
As such, it has a minimum
hence for minimum value; x = -b/2a
x = -(-8)/2 x 2
x = 8/4 = 2
plugging the values of x in f(x) ; f(2) = 2(2)^2 -8(2) + 5
f(2) = -3, hence it has minimum value and the minimum value is -3
Let's first find the slope. This is (y_2 - y_1)/(x_2 - x_1), where (x_1, y_1) and (x_2, y_2) are points.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is

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mhorn seems to be correct
Step-by-step explanation:
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