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Lelu [443]
2 years ago
12

What is the distance between the points -1 ,8 and 7,8 in the coordinate plane

Mathematics
2 answers:
Sav [38]2 years ago
7 0

Answer: 8 units

Step-by-step explanation:

To find the distance between 2 points, we want to use the formula d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Since we are given the 2 points, all we have to do is plug them in.

d=\sqrt{(7-(-1))^2+(8-8)^2}      [parenthesis]

d=\sqrt{(8)^2+(0)^2}                        [exponent]

d=\sqrt{64+0}                               [add]

d=\sqrt{64}                                     [square root]

d=8

Now, we know the distance is 8 units.

dimulka [17.4K]2 years ago
4 0
I think the answer is 9?
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Rectangle STUV has square PQRS removed, leaving an area of 92 m^2. Side PT is 4 m in length and side RV is 8m in length
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117 m^{2}

Step-by-step explanation:

First think of the square that was removed.  All 4 sides are equal but you don't know the length so lets gives them the variable X.

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Now plug in the numbers you know and solve for X.

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Use FOIL to multiply the first part of the equation (first, outer, inner, last)

32 + 8x + 4x + x^{2} -  x^{2}  =  92

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