Answer:
a) f g(x) = x³ - 5 x² + x -5
b) g(f(x) = x³ - 5 x² + x -5
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that f(x) = x² + 1 and g(x) = x-5
a)
f(g(x)) = f(x-5) = (x-5)²+1 = x² - 10x +25 +1 = x² - 10 x +26
<u><em>Step(ii):-</em></u>
a) f g(x) = f(x) g(x) = (x² + 1 )(x-5) = x³ - 5 x² + x -5
b) g(f(x) = g(x) f(x) = (x-5) (x²+1) = x³ - 5 x² + x -5
Answer:
A no. ans is 17a/20
B no. ans is 10c-7d/35
C no. ans is +1/−1⋅2/2⋅−1⋅3/2⋅−1⋅4
<h2>I only know this much answer.</h2><h3>Sorry. but hope this is helpfull.</h3>
Hello :
sin(x) + cos(x) = √2(1/√2 sin(x) +1/√2 cos(x))
but : 1/√2 = cos(π/4) = sin(<span> π/4)
</span>sin(x) + cos(x) = √2( cos(π/4)sin(x) + sin( π/4) cos(x)) =√2<span>sin(x + π/4)
</span>because : cos(π/4)sin(x) + sin( π/4) cos(x)=sin(x + π/4) by identity :
sin(a+b) = sina cosb +cosa sinb
D. f(x)=4 (5/2)^x
Are really good tool for graphing problems is Demos.com
