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3 years ago

13

PLZ HELP: the answer to 5(x-1) the answer to this cannot be found online. THIS IS SIMPLE MATH I'M STILL CONFUSED SO PLZ EXPLAIN

AND WORK OUT MATHEMATICALLY.

1 answer:

777dan777 [17]3 years ago

4 0

That would be 5x-5 because the number inside is multiplied by the numbers inside due to the brackets. Hope u understand my explanation.

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What is the range of y = sin θ ?

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For the answer to the question above, For θ the range is between -infinity and infinity,
<span>While y falls in the range from -1 to 1.
because </span><span>y is an element of [-1, 1]</span>
I hope my answer helped you in your problem. Have a nice day!

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3 years ago

Reflect quadrilateral SQRT over the y-axis. Then translate the new quadrilateral 3 units to the right. What are the coordinates

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Answer: S(-5;3) Q(-2;2) R(-3;-2) T(-6;-1)

When reflected over the y-axis, their x values will change sign

S(5;3) Q(2;2) R(3;-2) T(6;-1)

Translate 3 units to the right, their x values will increase by 3

S(8;3) Q(5;2) R(6;-2) T(9;-1)

Step-by-step explanation:

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3 years ago

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Use counting rules to find the following probabilities.

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Answer:

0.00144

Step-by-step explanation:

(13/1)(4/3)(12/1)(4/2)/(52/5)=(13)(4)(12)(6)/2598960=3744/2598960≈0.00144

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4 years ago

*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4

Georgia [21]

$\qquad\qquad\huge\underline{{\sf Answer}}$

$\textbf{Let's get it solved :}$

$\sf{x² = \dfrac{1}{4}}$

$\sf{x = \sqrt{\dfrac{1}{4}}}$

$\sf{x= \pm{\dfrac{1}{2}}}$

$\sf{x ={\dfrac{1}{2}} }$

$\textsf{[ since we need positive solution ]}$

$\textsf{Correct choice is C}$

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3 years ago

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In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from

Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

<em>a. </em>

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals $\frac{180}{600}=0.3$ ie 30%

<em>b.</em>

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

<em>c.</em>

z-score of the sample proportion assuming null hypothesis is:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of working people aged 65–69 (0.3)
p is the proportion assumed under null hypothesis. (0.27)
N is the sample size (600)

then z= $\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } }$ = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

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3 years ago

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