Why is it important to reduce radicals

1 answer:

7 0

Simplifying radical expressions expression is important before addition or subtraction because it you need to which like terms can be added or subtracted. If we hadn't simplified the radical expressions, we would not have come to this solution. In a way, this is similar to what would be done for polynomial expression.

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How to solve x=6y-11 and 3x-2y=-1 by substitution

vagabundo [1.1K]

Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest

7 0

3 years ago

How many days would it take a construction loan of $548,048 to earn$50,000 exact interest at 9% interest rate?

san4es73 [151]

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &50000\\
P=\textit{original amount deposited}\to& \$548048\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years
\end{cases}
\\\\\\
50000=548048\cdot 0.09t\implies \cfrac{50000}{0.09(548048)}=t\implies 1.014\approx t$

8 0

3 years ago

Read 2 more answers

the table below shows the function of f determine the value of f(3) that will lead to an average rate of change of 19 over the i

3241004551 [841]

ANSWER

$f(3) = - 25$

EXPLANATION

We want to determine the value of f(3) that will lead to an average rate of change of 19 over the interval [3, 5].

The average rate of change of f(x) over the interval [a,b]:

$= \frac{f(b) - f(a)}{b - a}$

If the average rate of change over the interval [3, 5] is 19, then;

$\frac{f(5) - f(3)}{5 - 3} = 19$

From the to table f(5)=13

$\frac{13 - f(3)}{2} = 19$

$13 - f(3) = 19 \times 2$

$13 - f(3) = 38$

$- f(3) = 38 - 13$

$- f(3) = 25$

$f(3) = - 25$

7 0

3 years ago

choose a non-piecewise function f(x) such that it’s Domain is all x≤5. Find the values of your function for x={−2,−1,0,1,2,3,4,5

iren2701 [21]

Answer:

f(x) = √(5-x)

Step-by-step explanation:

The square root is only defined for non-negative arguments. Here, we give it an argument that is only non-negative for x ≤ 5, thus satisfying the requirement for your function. The attached shows a table of values and a graph of it.