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vfiekz [6]
2 years ago
6

Andrea is traveling with her family in the car. If the car is moving at an average speed of 55 miles per hour, how many miles ca

n they travel in 4 hours? Use the formular. t, where r represents the rate, or speed, and t represents the time.
a. 554 miles
b. 220 miles
c. 200 miles
d. 59 miles​
Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0
Rate * time = distance traveled
55 * 4 = 220 miles
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okay so we have this question of the week thing and this week our answer is 47 so i need a algebra problem that equals 47 can so
mestny [16]

Answer: 5 times 5 plus 11 plus 11

Step-by-step explanation:

Creating an algebra problem that equals to 47.

5 times 5 is 25

25 plus 11 is 36

36 plus 11 is 47

6 0
3 years ago
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The following graph represents the distance a commercial airplane travels over time, at cruising speed and an altitude of 35,000
ANEK [815]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in hours

y ----> the distance in miles

<em>Find the value of k</em>

For the point (4,2268)

k=\frac{2,268}{4}=567\ mph

The slope represent the speed of the airplane

so

The linear equation is

y=567x

Part 1 :

The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.

Part 2 :

The  point  (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours

3 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
2p^2+10=0 <br><br> Please help!
ohaa [14]
2p^2+10=0\ \ \ |-10\\\\2p^2=-10\ \ \ |:2\\\\p^2=-5
No real solutions, because for all real numbers the square of number is greater or equal 0.


7 0
3 years ago
Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationa
Dimas [21]
These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match. 

Hope this helps!
5 0
3 years ago
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