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3 years ago

Need help omg I’ve been stuck

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

Answer:

x = -2.75

Step-by-step explanation:

14 - 3 = 11

11 / -4 = -2.75

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Show the working for <br><br> 3y^2 x 2y^5 x 5y^4 over 6y^3 x 4y^4

solong [7]

Answer:

please I can't do it I have not been thought

6 0

2 years ago

There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And

hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

Therefore;

n(C) = n(A∪B∪C) - (n(A) + n(B) - n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 - 170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

5 0

3 years ago

Solve for x & y solve x = 3 + yy = -2x + 9

sergey [27]

x = 3 + y Eqn(1)

y = -2x + 9 Eqn(2)

Let us solve the system of equations with the substitution method

x - 3 = y (Subtracting 3 from both sides of the Eqn(1))

Replacing y = x - 3 in Eqn (2), we have:

x - 3 = -2x + 9

x = -2x + 9 + 3 (Adding 3 to both sides of the equation)

x + 2x = 9 + 3 (Adding 2x to both sides of the equation)

3x = 12 ( Adding like terms)

x = 12/3 (Dividing by 3 on both sides of the equation)

x = 4

Replacing x=4 in Eqn(1), we have:

4 = 3 + y

4 - 3 = y (Subtracting 3 from both sides of the equation)

y=1

The answers are:

x= 4 and y=1

6 0

1 year ago

Math help what is the answer will give brainliest.

artcher [175]

The two equations are
$x + y = 7$
and
$4x + 2.5y = 22$
the first equation can be solved for x to be
$x = 7 - y$
next you can substitute x in the second equation
$4(7 - y) + 2.5y = 22$
Distribute 4 to everything in the parentheses
$28 - 4y + 2.5y = 22$
combine like terms:
$28 - 1.5y = 22$
subtract 28 from both sides of the equation
$- 1.5y = - 6$
divide both sides by -1.5
$y = 4$
plug this in to the original equation of x+y=7
$x + 4 = 7$
subtract 4 from both sides.
$x = 3$
Final Answer: they bought 3 adult tickets and 4 student tickets

Hope this helps!

7 0

3 years ago

H/j = 15 solve for j

solniwko [45]

H/j = 15 solve for j

j = h/15

7 0

3 years ago