Answer:
Step-by-step explanation:
![7- \sqrt[3]{2-x} =12](https://tex.z-dn.net/?f=7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12)
we have to just keep in mind to do the same operation to both sides of the equal sign
![7-7- \sqrt[3]{2-x} =12-7](https://tex.z-dn.net/?f=7-7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12-7)
; subtract 7 from both sides
![- \sqrt[3]{2-x} = 5](https://tex.z-dn.net/?f=-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D%205)
; multiply both sides by -1
![\sqrt[3]{2-x} = -5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2-x%7D%20%3D%20-5)
; raise both sides to the power 3
2-x = (-5)³
2-x = -125 ; subtract 2 from both sides
-x = -125-2
-x =-127; multiply both sides by -1
x= 127
Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>
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Problem 2
Now we'll use the quotient rule
<h3>Answer: -2/9</h3>
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Problem 3
Use the chain rule
<h3>Answer: 12</h3>
Answer:
Choice B) No.
Step-by-step explanation:
When she starts , she does a sit-up every 222 seconds.
But as she gets tired, each sit-up takes longer and longer to do.
It means, each sit-up takes more time than she did at beginning.
So, it is NOT proportional to the time.
If it is proportional, she should take constant number of sit-ups even she get tired.
-64 + -4 = -68
That is because 64 + 4 = 68 and the negatives in this case are the same way as if it was all positive.
Answer:
x= -8 , y = 5
x= 25/4 , y = 1/4
Step-by-step explanation:
substitute first eqn into the second eqn:
(7 - 3y)^2 -y^2 = 39
49 - 42y + 9y^2 - y^2 = 39
8y^2 - 42y +10 =0
4y^2 - 21y + 5 = 0
(4y-1) (y-5) = 0
y= 1/4 , 5
when y=1/4
x = 7- 3/4
=25/4
when y= 5
x = 7- 15
= -8
