<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
Answer: 12 packages
Step-by-step explanation:
<em>Take 175 and divide it by 15</em>
<em>175/15</em>
<em>You will get 11.6</em>
<em>Since you are unable to order 11.6 packages you will need to order </em><em>12</em><em> packages to have enough lightbulbs.</em>
Answer:
64%
Step-by-step explanation:
16 divided by 25 is 0.64 then multiply by 100 to convert a decimal to a percentage which equals 64%.
Answer:
lol imagine
Step-by-step explanation:
47 - 19 = 28
28/4 = 7
At most they can spend 7 hours
The solution is
T = (47-19)/4
T = 28/4
T = 7
I think that solution is what your teacher is asking for, i'm not certain but ik the answer should be 7 hours.
