All categories

3 years ago

Given tantheta = 4/3 and pi < theta < 3pi/2; find cos2theta

Mathematics

2 answers:

Sidana [21]3 years ago

8 0

Answer:

d. -7/25

Step-by-step explanation:

π<θ<3π/2 in third quadrant

tanθ = 4/3

sinθ = - 4/5

cosθ = - 3/5

cos 2θ = cos²θ - sin²θ = (- 3/5)² - (- 4/5)² = 9/25 - 16/25 = - 7/25

UkoKoshka [18]3 years ago

4 0

Answer:

-24/7

Step-by-step explanation:

We know that,

tan

−

tan

∴

tan

⋅

−

⋅

You might be interested in

The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand

alexira [117]

Answer:

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

t = 1.076

Step-by-step explanation:

Step(i):-

Given Mean of the Population (μ) = 8.0

Mean of the sample (x⁻) = 8.25

Given data

8,9,9,8,8,9,8,7

Given sample size n= 8

Given sample standard deviation(S) = 0.661

Step(ii):-

Null hypothesis : H: (μ) = 8.0

Alternative Hypothesis :H:(μ) > 8.0

Degrees of freedom = n-1 = 8-1=7

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }$

t = 1.076

Critical value

t₍₇,₀.₀₅₎ = 2.3646

The calculated value t = 1.076 < 2.3646 at 0.05 level of significance

Null hypothesis is accepted

Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0

3 0

2 years ago

The original price for a jacket was 124.95. It is on sale for 20% off. Witch of the following gives the best estimate of the sav

d1i1m1o1n [39]

20% of 124.95 is close to $125 so that is equal of 12.50 of 10% so multiply by 2 which is $25.00 so the estimate discount of the jacket will be $25.00

7 0

3 years ago

Read 2 more answers

Solve (x-3) (x+2) = 0 and x² - 25

Nookie1986 [14]

Answer:

its 2 x I think u can defirantate

7 0

3 years ago

Read 2 more answers

the function h(t)=-16t^2+110t+72 models the height h, in feet, of an object above ground t seconds after being launched straight

Anettt [7]

Answer:

The initial height of an object above ground before being launched straight up in the air

Step-by-step explanation:

we have

$h(t)=-16t^{2}+110t+72$

we know that

The number 72 represent the y-intercept of the function

The y-intercept is the value of y when the value of x is equal to zero

In this problem

The value of h when the value of t is zero

Therefore

The initial height of an object above ground before being launched straight up in the air

7 0

2 years ago

Equations

Flauer [41]

Answer:

Step-by-step explanation:

-3x + 4y = -18

8x - 4y = 28

5x = 10

x = 2

4 - y = 7

-y = 3

y = -3

(2, -3)

8 0

3 years ago

Read 2 more answers