What is 63 tenths less than 8.13?

Determine the solution to the system of equation below, algebraically. 5x+3y=28 x+y=8

VladimirAG [237]

Is this what you're asking for?

5 0

3 years ago

Process control is nothing more or less than monitoring quality as the work is being performed. Perhaps the most widely adopted

ella [17]

Answer:

a. Grand Mean = 2.799

b. Standard Deviation = 0.01387

c. Standard Error = 0.0016

d. The range with a Z score of 3 = (2.75739, 2.84061)

Step-by-step explanation:

a. Grand mean :

Given that

Sum of 80 values = 223.91

Total observation = 80

Grand mean = 223.91/80 = 2.799

b. With the excel command "STDEV[range of cells]", we get the standard deviation as = 0.01387

c. Standard error = Standard deviation / root of n

$= 0.01387/\sqrt{80}\\ = 0.0016$

d. The range with a Z score of 3 :

lower limit = mean - (3 * SD) = 2.799 - (0.04161) = 2.75739

upper limit = mean + (3 * SD) = 2.799 + (0.04161) = 2.84061

8 0

3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term $x^2$ , which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression: $x_v=\frac{-b}{2a}$

Since in our case $a=1$ and $b=5$ , we get that the x-position of the vertex is: $x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

$y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}$

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the $x_v=-\frac{5}{2}$ . Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

$f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0$

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0

3 years ago

!!!HELP PLEASE !!!!!

Fofino [41]

Tree 3 diagram is the answer

8 0

3 years ago

The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 8

julsineya [31]

Good afternoon,

First side= 8cm
Third side= x
Second side= 2x-4

We know that the sume of the lenghts of any two sides must be greater than the third side, so:

$Second \,\,\,\,side+Third\,\,\,\,side>First\,\,\,\,side \\ 2x-4 + x >8 \\ 3x>12 \\ x>4
$

Answer: Third side= x ; where: x>4 or (4,+infinity)
Second side= 2x-4 ; where: x>4 or (4,+infinity)

3 0

3 years ago

What is 63 tenths less than 8.13?​

What is 63 tenths less than 8.13?