Find the area of this parallelogram

I need help with 1-9! please help

Sav [38]

1-First let’s list the numbers between 210 to 220, except the even ones since they’re a multiple of 2:

211; 213; 215; 217; 219

Let’s remove 213, and 219 because they’re multiples of 3 (2+1+3=6; 2+1+9=12), 215 is multiple of 5, so let’s remove it.

That leave’s is with 211, and 217.

We can remove 217, because it’s a multiple of 7, leaving us with 211.

2- It’s deductive reasoning, because you started with a more general idea.

3- {-7, -6, -5, -4, -3, -2, -1, 0, 1}

4- {x e R, x>=-2}

5-{-1, 0, 1}

6- {x∣-4≤ x ≤6}

7- [-20, ♾ )

8- On a number line, make a circle around -1, and continue the line to minus infinity.

9- On a number line, make a circle on -3, and continue to minus infinity. Make a ring on 0, and continue to infinity.

7 0

3 years ago

What is the simplest form of square root of

AveGali [126]

First step is to simplify the inside of the radical. There are x's on both top and bottom of the fraction. So we subtract their exponents. x³ - x¹ = x². Because the x³ was in the denominator and it was bigger, the x² goes on the bottom.

Your new equation is:

$\sqrt{\frac{126y^{5}}{32x^{2}} }$

Now, I'd suggest factoring each term to correspond with the square root.

126y⁵ = 9 · 14 · y² · y² · y

32x² = 4 · 4 · 2 · x²

9, y², and y² can be square rooted in the numerator. 4, 4, and x² in the denominator. So we pull out their square roots and place them outside of the radical. The rest stays in the radical:

$\frac{3 * y * y}{2*2*x}\sqrt{\frac{14y}{2}}$